quality category - перевод на итальянский
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quality category - перевод на итальянский

Dg category; Dg-category; DG category; DG-category

quality category      
gruppo di alto livello (nell"esercito)
quality circles         
GROUP OF WORKERS WHO MEET REGULARLY TO IDENTIFY, ANALYZE AND SOLVE WORK-RELATED PROBLEMS
Quality circles; Quality Circles; Quality control circle; Management quality circle
circoli selezionati (sistema di istituzione di gruppi di lavoro per la discussione e soluzione dei problemi inerenti a ciascun gruppo)
quality assurance         
WAY OF PREVENTING MISTAKES OR DEFECTS IN MANUFACTURED PRODUCTS AND AVOIDING PROBLEMS WHEN DELIVERING SOLUTIONS OR SERVICES TO CUSTOMERS; (ISO 9000) PART OF QUALITY MANAGEMENT FOCUSED ON PROVIDING CONFIDENCE THAT QUALITY REQUIREMENTS WILL BE FULFILLED
Quality assessment; Quality Assessment; Quality Assurance; Systems assurance; Quality assurance program; Aseguradores de la calidad; QA Engineer
assicurazione di qualità, controllo di qualità di un prodotto prima di immetterlo sul mercato

Определение

quality circle
A quality circle is a small group of workers and managers who meet to solve problems and improve the quality of the organization's products or services. (BUSINESS)
Riddick's first move was to form a quality circle.
N-COUNT

Википедия

Differential graded category

In mathematics, especially homological algebra, a differential graded category, often shortened to dg-category or DG category, is a category whose morphism sets are endowed with the additional structure of a differential graded Z {\displaystyle \mathbb {Z} } -module.

In detail, this means that Hom ( A , B ) {\displaystyle \operatorname {Hom} (A,B)} , the morphisms from any object A to another object B of the category is a direct sum

n Z Hom n ( A , B ) {\displaystyle \bigoplus _{n\in \mathbb {Z} }\operatorname {Hom} _{n}(A,B)}

and there is a differential d on this graded group, i.e., for each n there is a linear map

d : Hom n ( A , B ) Hom n + 1 ( A , B ) {\displaystyle d\colon \operatorname {Hom} _{n}(A,B)\rightarrow \operatorname {Hom} _{n+1}(A,B)} ,

which has to satisfy d d = 0 {\displaystyle d\circ d=0} . This is equivalent to saying that Hom ( A , B ) {\displaystyle \operatorname {Hom} (A,B)} is a cochain complex. Furthermore, the composition of morphisms Hom ( A , B ) Hom ( B , C ) Hom ( A , C ) {\displaystyle \operatorname {Hom} (A,B)\otimes \operatorname {Hom} (B,C)\rightarrow \operatorname {Hom} (A,C)} is required to be a map of complexes, and for all objects A of the category, one requires d ( id A ) = 0 {\displaystyle d(\operatorname {id} _{A})=0} .